Hyperbola - Maroon
Parabola - Red
Ellipse - Orange
Blue Dots - Foci
Green - Path of foci
This curve is a strophoid.
Thank you to Jean-Pierre Ehrmann of France for telling me this.
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In sci.math Alexander Bogomolny wrote that this curve is traced by the point of intersection of the lines whose velocities are in the ration of 1:2. See Lighthouse
-
Clive Tooth followed Alexander's post
with a demonstration 
using a Dandelin sphere: 
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Consider a cone.
Let the vertex of
the cone be V
and let g be a generator.
Call the axis of the cone x.
Let A be a fixed point on g. 
Let B be the point on x
which is closest to A.
Let r be the line through A
which is tangential
to the cone and which is
perpendicular to g.
(r is not visible
in this diagram because it's perpendicular to the screen)
-
Consider the pencil of
planes through r. 
Let P be one of these planes.
P will intersect our cone in some conic section. 
Consider a sphere, center C,
inscribed in the cone
and touching P, at a point F.
It is well known that F is a
focus of our conic section.
-
Clearly C is on x and the points
ABC and F are in the same plane.
-
Consider
the angle that AF
makes with g,
on the side of P
away from the sphere.
Call this angle 2t.
Now the angles
CBA and CFA are
both right angles.
So the points ABC & F
are concyclic.
So the angle ACF
is equal to
the angle ABF.
But the angle CAF is
(pi-2t)/2 = pi/2 - t,
so the angle ACF is t,
so the angle ABF is t.
-
Thus, A and B
are fixed points such that
for any position of
the plane P,
the angle gAF
is twice the angle ABF.
-
Thus, the point F
is the intersection
of two rotating lines
(BF and AF)
whose angular velocities
are in the ratio 1:2.
-
QED
-

 
Thanks to Alexander and Clive, I can now see this curve as part of a moire pattern generated by two families of radial lines.

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